A tangent from a point P outside the circle meets the circle at M. Then $∠ M O P =$ , if $∠ M P O = 30^{\circ}$ .

30^{\circ}

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60^{\circ}

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45^{\circ}

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Solution

The correct option is B $60^{\circ}$
Angle between MP and OM is $90^{\circ}$ and $∠ M P O = 30^{\circ} .$

$∴ ∠ M O P = 180^{\circ} - (90^{\circ} + 30^{\circ}) = 60^{\circ}$

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A tangent from a point P outside the circle meets the circle at M. Then ∠MOP= , if ∠MPO=30∘.

The correct option is B 60∘Angle between MP and OM is 90∘ and ∠MPO=30∘. ∴∠MOP=180∘−(90∘+30∘)=60∘

A tangent from a point P outside the circle meets the circle at M. Then $∠ M O P =$ , if $∠ M P O = 30^{\circ}$ .

The correct option is B $60^{\circ}$
Angle between MP and OM is $90^{\circ}$ and $∠ M P O = 30^{\circ} .$

$∴ ∠ M O P = 180^{\circ} - (90^{\circ} + 30^{\circ}) = 60^{\circ}$