The correct options are
B y12,a,y2 are in G.P.
C −4,y1y2,x1x2 are in G.P.
D x1x2+y1y2=a2
Let (x1,y1)=(at2,2at)
Tangent at this point is
ty=x+at2
Any point on this tangent will be
(h,h+at2t) .
Chord of contact drawn from this point on the circle is T=0
⇒hx+(h+at2)ty=a2
⇒aty−a2+h(x+yt)=0
It represents the family of straight lines through the points of intersection of
ty−a=0 and x+yt=0
So, the fixed point is (x2,y2)=(−at2,at)
(x1,y1)=(at2,2at)
Clearly, x1x2=−a2
So, x1,a,x2 are not in G.P.
y1y22=a2
So, y12,a,y2 are in G.P.
x1x2=−t4, y1y2=2t2
−4×x1x2=(y1y2)2
So, −4,y1y2,x1x2 are in G.P.
x1x2+y1y2=−a2+2a2=a2