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Question

A tangent is drawn at any point (x1,y1) other than the vertex on the parabola y2=4ax. Tangents are drawn from any point of this tangent to the circle x2+y2=a2 such that all the chords of contact passes through a fixed point (x2,y2). Then

A
x1,a,x2 are in G.P.
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B
y12,a,y2 are in G.P.
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C
4,y1y2,x1x2 are in G.P.
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D
x1x2+y1y2=a2
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Solution

The correct option is D x1x2+y1y2=a2
Let (x1,y1)=(at2,2at)
Tangent at this point is
ty=x+at2
Any point on this tangent will be
(h,h+at2t) .
Chord of contact drawn from this point on the circle is T=0
hx+(h+at2)ty=a2
atya2+h(x+yt)=0
It represents the family of straight lines through the points of intersection of
tya=0 and x+yt=0
So, the fixed point is (x2,y2)=(at2,at)

(x1,y1)=(at2,2at)
Clearly, x1x2=a2
So, x1,a,x2 are not in G.P.

y1y22=a2
So, y12,a,y2 are in G.P.

x1x2=t4, y1y2=2t2
4×x1x2=(y1y2)2
So, 4,y1y2,x1x2 are in G.P.

x1x2+y1y2=a2+2a2=a2

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