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Byju's Answer
Standard XII
Mathematics
Derivative from First Principle
A tangent is ...
Question
A tangent is drawn at the point M (1, 8) to the curve
y
=
√
(
5
−
x
2
/
3
)
3
.
Find the length of its segment included between the coordinate axes.
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Solution
y
=
√
(
5
−
x
2
3
)
3
d
y
d
x
=
3
2
(
5
−
x
2
3
)
1
2
.
(
−
2
3
x
−
1
3
)
d
y
d
x
∣
∣
∣
x
=
1
=
−
2
For tangent at
M
(
1
,
8
)
⇒
y
−
8
x
−
1
=
−
2
⇒
2
x
+
y
=
10
⇒
x
5
+
y
10
∴
Length of the segment
=
√
5
2
+
10
2
=
5
√
5
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