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Question

A tangent to an ellipse x2a2+y2b2=1 meets the co-ordinate axes in P and Q. The least value of PQ is

A
ab
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B
a+b
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C
a+b2
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D
2a
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Solution

The correct option is B a+b
Ellipse: x2a2+y2b2=1
T be the tangent to ellipse on any point, Let T intersect axis in P and Q. we know that the shortest distance between P and Q is equal to sum of semi major axis and semi minor axis. So PQmin=2a2+2b2=a+b

1018522_1018707_ans_ff572d40c0b04209810a67c6bb98aed2.png

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