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Question

A tangent to the parabola x2=4ay meets the hyperbola xy=k2 in two points P & Q, then find the locus of the middle point of PQ :

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Solution

Equation of tangent to parabola x2=4ay is ymx+am2=0 ....(i)
Let mid point of PQ is (x1,y1)
Then equation of PQ is
xy1+yx1=2k2 ....(ii)
On comparing (i) & (ii)
x11=y1m=2k2am2
x1=2k2am2 .....(iii)
y1=2k2am .....(iv)
using (iii) & (iv) eliminate m to get required locus,
y2=2k2ax which is a parabola.

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