A tank 10 m X 5 m X 6 m is full of water The amount of water taken out to reduce out to reduce the water level by one metre is

m^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

m^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 50 $m^{3}$
Given length , breadth and height of tank is 10 m, 5 m and 6 m respt
Then total volume of tank= $10 \times 5 \times 6 = 300 m^{3}$
If one meter water level reduced then volume reduced water= $10 \times 5 \times 1 = 50 m^{3}$

Suggest Corrections

Similar questions

Q. A tank

10 m \times 5 m \times 6 m

is full of water.The amount of water taken out to reduce the water level by one metre is

Q. The time taken to empty a water tank of capacity

1024 m^{3}

at the rate of

64 \frac{m^{3}}{m i n}

is .

A pipe is connected to a tank. The water flows out from the tank through the pipe at the rate of $64 \frac{m^{3}}{m i n}$ . Find the time taken by the pipe to empty the volume of $1024 m^{3}$ .(in mins)

Q. A water treatment plant capacity,

1 m^{3} / s

has filter boxes of dimension

6 \times 10 m

. Loading rate to the filter is

120 m^{3} / d a y / m^{2}

. When two of the filters are out of service for back washing, the loading rate (in

m^{3} / d / m^{2})

Q. The amount of work done is pumping water out of a cubical vessel of height 1 m is nearly (Given

ρ_{w a t e r} = 1000 k g / m^{3}

)

Join BYJU'S Learning Program

A tank 10 m X 5 m X 6 m is full of water The amount of water taken out to reduce out to reduce the water level by one metre is

The correct option is A 50 m3Given length , breadth and height of tank is 10 m, 5 m and 6 m resptThen total volume of tank=10×5×6=300m3If one meter water level reduced then volume reduced water=10×5×1=50m3

The correct option is A 50 $m^{3}$
Given length , breadth and height of tank is 10 m, 5 m and 6 m respt
Then total volume of tank= $10 \times 5 \times 6 = 300 m^{3}$
If one meter water level reduced then volume reduced water= $10 \times 5 \times 1 = 50 m^{3}$