Question

A tank $4m$ high is half filled with water then filled to the top with a liquid of density $0.60g/cc$ what is the pressure at the bottom of the tank due to these liquids? (take $g=10m{s}^{-2}$)

• A. $1.6\times {10}^{3}N{m}^{-2}$
• B. $3.2\times {10}^{-3}$
• C. $1.6\times {10}^{4}N{m}^{-2}$
• D. $3.2\times {10}^{4}N{m}^{-2}$

Answer 1

Answer: (D)

$3.2\times {10}^{4}N{m}^{-2}$

We know that pressure at Bottom

P=${\rho }_{1}g{h}_1+{\rho }_{2}g{h}_2$

Given

${\rho }_1=1g/c_c={\mathrm{1000}}^{}{k}_g/m^3$

${\rho }_2=0.6g/c_c=\mathrm{600}kg/m^3$

$h_1=4/2=2=t_2$

$g=10m/s^2$

$P=\mathrm{1000}\times 10\times 2+600\times 10\times 2$

$=20000+12000=3.2\times {10}^4{Nm}^{-2}\text{Answer:}\left(D\right)$