A tank $5 m$ high is half filled with water and then is filled to the top with oil of density $0.85 g c m^{- 3}$ . The pressure at the bottom of the tank, due to these liquids is

1.85 g d y n e c m^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

89.25 g d y n e c m^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

462.5 g d y n e c m^{- 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

500 g d y n e c m^{- 2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $462.5 g d y n e c m^{- 2}$
So the tank is filled with water upto $h_{1} = 2.5 m = 250 c m$ and remaining $h_{2} = 2.5 m = 250 c m$ with oil .
So $P = ρ_{w a t e r} g h_{1} + ρ_{o i l} g h_{2}$
$P = (1) (250) g + (0.85) \times (250) g$
$P = 462.5 g d y n e c m^{- 2}$

Suggest Corrections

Similar questions

Q. A tank

5 m

high is half filled with water and then is filled to the top with oil of density

0.85 g c m^{- 3}

. The pressure at the bottom of the tank, due to these liquids, is

Q. A tank

2 m

high is half filled with water and then filled to the top with oil of density

0.80 g / c c

. What is the pressure at the bottom of the tank due to these liquids (Take

g = 10 m s^{- 2}

) is

A tank 5 m high is half filled with water and then is filled to the top with oil of density $0.85 g / c m^{3}$ . The pressure at the bottom of the tank, due to these liquids is

Q. A tank 5 m high is half - filled with water and then is filled to the top with oil of density

0.85 g / c m^{3}

. The pressure at the bottom of the tank, due to these liquids is:-

Q. A 5m tank is half filled with water and half with oil of density 0.85 g/cc. The pressure at the bottom is

Join BYJU'S Learning Program

A tank 5 m high is half filled with water and then is filled to the top with oil of density 0.85 g cm−3. The pressure at the bottom of the tank, due to these liquids is

The correct option is C 462.5 g dyne cm−2So the tank is filled with water upto h1=2.5m=250cm and remaining h2=2.5m=250cm with oil .So P=ρwatergh1+ρoilgh2P=(1)(250)g+(0.85)×(250)gP=462.5gdynecm−2

A tank $5 m$ high is half filled with water and then is filled to the top with oil of density $0.85 g c m^{- 3}$ . The pressure at the bottom of the tank, due to these liquids is

The correct option is C $462.5 g d y n e c m^{- 2}$
So the tank is filled with water upto $h_{1} = 2.5 m = 250 c m$ and remaining $h_{2} = 2.5 m = 250 c m$ with oil .
So $P = ρ_{w a t e r} g h_{1} + ρ_{o i l} g h_{2}$
$P = (1) (250) g + (0.85) \times (250) g$
$P = 462.5 g d y n e c m^{- 2}$