A tank has a leak which would empty it in 10 hours,a tap is turned on which admits 4 litre a minute into the tank and now it emptied in 15 hours.The capacity of the tank(in litres) is:

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Solution

$5$ hours of leak $= 15$ hours of tap
$1$ hour of leak $= 3$ hours of tap
$10$ hour of leak $= 30$ hours of tap
$∴$ tap can fill the tank in $30$ hours.
Water admitted by tap in $30$ hours $= 30 \times 60 \times 4 = 120 \times 60 = 7200$ litres.

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A tank has a leak which would empty it in 10 hours,a tap is turned on which admits 4 litre a minute into the tank and now it emptied in 15 hours.The capacity of the tank(in litres) is:

5 hours of leak=15 hours of tap1 hour of leak=3 hours of tap10 hour of leak=30 hours of tap∴tap can fill the tank in 30 hours.Water admitted by tap in 30 hours=30×60×4=120×60=7200litres.

$5$ hours of leak $= 15$ hours of tap
$1$ hour of leak $= 3$ hours of tap
$10$ hour of leak $= 30$ hours of tap
$∴$ tap can fill the tank in $30$ hours.
Water admitted by tap in $30$ hours $= 30 \times 60 \times 4 = 120 \times 60 = 7200$ litres.