A tank is filled with water and two holes A and B are made in it. For getting same range, ratio of h′h is
A
1:2
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B
1:1
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C
2:1
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D
3:2
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Solution
The correct option is B1:1
Let the gap between the hole A and hole B is x For hole A, Velocity of efflux =√2g(x+h′) Range R=2√h(x+h′).....(1) For hole B, Velocity of efflux =√2gh′ Range, R=2√h′(x+h).....(2) But, range of liquid from hole A and B are equal. So, from equation (1) & (2), 2√h(x+h′)=2√h′(x+h) Squaring on both sides, h(x+h′)=h′(x+h) ⇒hx+hh′=h′x+hh′ ⇒h=h′ ⇒h′h=1