A tank is filled with water up to height H. When a hole is made at a distance h below the level of water. What will be a horizontal range of water jet?
A
2√h(H−h)
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B
4√h(H+h)
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C
4√h(H−h)
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D
2√h(H+h)
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Solution
The correct option is A2√h(H−h)
Velocity of efflux at hole = vx=√2g(H−h)
Time taken to reach the ground = √2hg
So horizontal range = velocity × time = √2g(H−h)×√2hg