Question

A tank of water has a pin hole leak in the side, $1m$ below the tank is open to the atmosphere (air pressure $=1.013X{10}^{5}pa$), how fast is the water leaving the pin hole?

• A. $\sqrt{\frac{g}{0.1}}$
• B. $\sqrt{\frac{g}{4}}$
• C. $\sqrt{g}$
• D. $\sqrt{2g}$

Answer 1

The correct option is D $\sqrt{2g}$

$\begin{array}{cc}\text{given}H=1mV=?& \\ \text{we know that}v=\sqrt{2gH}& \\ \begin{array}{cc}V& =\sqrt{2\times g\times 1}\\ V& =\sqrt{2g}\end{array}& \\ \text{Answer}:-\left(D\right)& \sqrt{2g}\end{array}$