A tap can empty a tank in one hour. A second tap can empty it in 30 minutes. If both the taps operate simultaneously, how much time is needed to empty the tank?
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Solution
1 hour =60 minutes
Rate of emptying the tank by the two taps are 160 and 130 of the tank per minute respectively.
Rate of emptying the tank when both operate simultaneously
=160+130=1+260=360=120
of the tank per minute.
∴ Time taken by the two taps together to empty the tank =20 minutes.