A tap can fill a tank in $6$ hours, but due to leakage in the bottom of tank it could be filled in $1$ hour more. If leakage can empty $6$ litre per minute, calculate the value of the tank.

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Solution

Tap can fill in 1 hour, $\frac{1}{6}$ of the tank.
But due to leakage it can fill $\frac{1}{7}$ of the tank in 1 hour.
$∴$ Leakage can empty
$\frac{1}{6} - \frac{1}{7} = \frac{1}{42}$ of the tank in 1 hour.
Hence,
$\frac{1}{42} t a n k = 6 \times 60 l i t . (1 h o u r)$
$∴$ Full tank (volume) $= 6 \times 60 \times 42 l i t . = 15, 120 l i t .$

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A tap can fill a tank in 6 hours, but due to leakage in the bottom of tank it could be filled in 1 hour more. If leakage can empty 6 litre per minute, calculate the value of the tank.

Tap can fill in 1 hour, 16 of the tank.But due to leakage it can fill 17 of the tank in 1 hour.∴ Leakage can empty16−17=142 of the tank in 1 hour.Hence,142tank=6×60lit.(1hour)∴ Full tank (volume) =6×60×42lit.=15,120lit.

A tap can fill a tank in $6$ hours, but due to leakage in the bottom of tank it could be filled in $1$ hour more. If leakage can empty $6$ litre per minute, calculate the value of the tank.