Question

A taper roller bearing has a dynamic load capacity of 26 kN. The desired life for 90% of the bearing is 9000 hr and the speed is 300 rpm. Calculate the equivalent radial load that the bearing can carry.

• A. 6250 N
• B. 4320 N
• C. 5650 N
• D. 6450 N

Answer 1

The correct option is C 5650 N

$C=26kN,L_{10}=9000hr,N=300rpm$

$\text{Bearing life}\left(L_{10}\right)=\frac{60\times N\times L_{10}}{{10}^6}$

$=\frac{60\times 300\times 9000}{{10}^6}=\text{162 million revolution}$

$\text{Let P be equivalent radial load}$

$\Rightarrow 162={\left(\frac{26\times {10}^{3}N}{P}\right)}^{\frac{10}{3}}\Rightarrow P=5650.9N$