A tapered roller bearing has a static load rating of 10 kN and a dynamic load rating of 15 kN. It is subjected to a static radial load of 2 kN and a thrust load of 1 kN. The radial load factor is 0.9 and thrust load factor is 1.2. Its life in millions of revolutions is

Open in App

Solution

$L_{90} = {(\frac{C}{P_{e}})}^{3} = {(\frac{15}{3})}^{3}$

$L_{90} = 125 million revolutions$

Suggest Corrections

Similar questions

A self-aligning ball bearing has basic dynamic load rating (C_{10}, for 10^{6} revolutions) of 35 kN. If the equivalent radial load on the bearing is 45 kN, the expected life (in 10^{6} revolutions) is

L_{90}

For ball bearings, the fatigue life L measured in number of revolutions and the radial load F are related by F L^{\frac{1}{3}} = K, where K is a constant. It withstands a radial load of 20 kN for a life of 540 million revolutions. The load (in kN) for a life of one million revolutions is

Join BYJU'S Learning Program