Question

A taut string fixed at both ends vibrates in $2^{\text{nd}}$ overtone. The distance between adjacent node and antinode is found to be d. If the length of the string is $L$, then value of $\frac{L}{d}$ is

• A. 6
• B. 5
• C. $\frac{11}{2}$
• D. $\frac{7}{2}$

Answer 1

The correct option is A 6

$\frac{\lambda }{4}=d$
$\frac{3\lambda }{2}=L$
$L=\frac{3\times 4d}{2}=6d$
$\frac{L}{d}=6$