Question

A taxi charges ₹15 for the first km and ₹8 for each additional km. The amount payable for 16 km is .

• A. ₹125
• B. ₹135
• C. ₹145

Answer 1

The correct option is B ₹135

Analysing the question carefully, we know that the taxi fare for each km will form an arithmetic progression.
The first term is 15 which is the fare for the first km.
The common difference is 8 which is the fare for each additional km.

Now, we need to find the fare for the first km and the fare for the remaining (n-1) additional km of distance travelled.

In this case, the distance of travel is 16 km.
So fare for the first km = ₹15
Fare for the rest 15 km = ₹8 per km

a = 15, d = 8, and n = 16
Therefore, fare = 16th term of the AP
$a_{16}=a+(n-1)d$
$a_{16}=15+(16-1)8$
$a_{16}=15+15\times 8$
$a_{16}=135$
Hence, the amount payable is ₹135.