wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A team consists of 6 boys and 4 girls and other has 5 boys and 3 girls. How many single matches can be arranged between the two teams when a boy plays against a boy and a girl plays against a girl?

Open in App
Solution

A boy can be selected from the first team in 6 ways, and from the second in 5 ways, So, number of single matches between the boys of two teams = 6×5=30 Similarly, the number of single matches between the girls of two teams = 4 \times 3 = 12 So, total number of matches = 30+12= 42.


flag
Suggest Corrections
thumbs-up
13
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Counting Principle
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon