Question

A team of 11 players has to be choosen from the groups consisting of 6 and 8 players respectively. The number of ways of selecting them so that each selection contains atleast 4 players from the first group is

• A. 120
• B. 280
• C. 344
• D. 244

Answer 1

Answer: (C)

344

First group(6)	Second group(8)	Number of ways of selection
4	7	${}^6{C}_4{.}^8{C}_7=15\times 8=120$
5	6	${}^6{C}_5{.}^8{C}_6=6\times 28=168$
6	5	${}^6{C}_6{.}^8{C}_5=1\times 8=56$

Hence required number of ways $=120+168+56=344$