A contractor undertakes to dig a canal, $6$ kilometers long, in $35$ days and employed $90$ men. He finds that after $20$ days only $2 k m$ of the canal have been completed. How many more men must be employed to finish the work in time?

Q. A certain number of men can finish a piece of work in 100 days. If, there were 10 men less, it would take 10 days more for the work to be finished. How many men were there originally ?

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A team of 30 men is supposed to do a work in 38 days. After 25 days, 5 more men were employed and the work was finished one day earlier. How many days would it have been delayed if 5 more men were not employed?

The correct option is D 1 day35 men completed the remaining job in 12 days.Now the same job has to be done by 30 men.We know that, M1D1=M2D2Required time =35×1230=14 daysDelayed time =(14−13)=1 day.

A team of $30$ men is supposed to do a work in $38$ days. After $25$ days, $5$ more men were employed and the work was finished one day earlier. How many days would it have been delayed if $5$ more men were not employed?

The correct option is D $1 d a y$
$35$ men completed the remaining job in $12 d a y s$ .
Now the same job has to be done by $30 m e n$ .
We know that, $M_{1} D_{1} = M_{2} D_{2}$
Required time $= \frac{35 \times 12}{30} = 14 d a y s$
Delayed time $= (14 - 13) = 1 d a y$ .