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Question

A team of 8 couples, (husband and wife) attend a lucky draw in which 4 persons picked up for a prize. Then, the probability that there is atleast one couple is

A
1139
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B
1239
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C
1439
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D
513
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Solution

The correct option is D 513
Total People Attending: 16
Ways To Choose 4 From 16: 16 x 15 x 14 x 13/4! = 1820
Ways To Choose 4 Without Any Couples: 16 x 14 x 12 x 10/4! = 1120
Ways To Choose 4 That Include One Or More Couple: 1820 - 1120 = 700
Probability Of Choosing At Least One Couple: 700/1820 = 35/91=5/13

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