Question

A Technician has to repair a light on a pole of height 10 m. She needs to reach a point 1 m below the top of the pole to undertake the repair work. What should be the length of the ladder that she should use which, when inclined at an angle of ${60}^{\circ }$ to the ground, would enable her to reach the required position? Also, how far from the foot of the pole should she place the foot of the ladder?

Answer 1

The given situation is represented by the figure below

DB - DC = CB
$\Rightarrow BC=9msin{60}^{\circ }=\frac{BC}{AC}\Rightarrow AC=\frac{BC}{sin{60}^{\circ }}=\frac{9}{\frac{\sqrt{3}}{2}}=\frac{18}{\sqrt{3}}=6\sqrt{3}m\therefore heightofladdershouldbe6\sqrt{3}m$