Question

A telephone link operating at a central frequency of $10GHz$ is established. If 1% of this is available, then how many telephone channel can be simultaneously given when each telephone covering a band width of $5kHz$ ?

• A. $2\times {10}^4$
• B. $2\times {10}^6$
• C. $5\times {10}^4$
• D. $5\times {10}^6$

Answer 1

The correct option is A $2\times {10}^4$

1% of $10GHz$ =$10\times {10}^9\times \frac{1}{100}={10}^{8}Hz$
Number of channels = $\frac{{10}^8}{5\times {10}^3}=2\times {10}^4$