The correct option is C ±1.05%
In the given sensor, there are two sources of error, one expressed as % true value and other as % full scale.
Also sensitivity of transducer =outputinput
⇒ Sensitivity=xT
where x is output of sensor at input temperature T.
Now, i.e., error in sensitivity,
(i) At 25°C/75°C due to ±1% of true value error in input only.
e1=x24.75−x25x25×100=±1.01%
e2=x74.25−x75x75×100=±1.01
(ii) At 25°C/75°C due to ±0.3% of full scale error in input only.
error in input (in °C)
=±100×0.3100=0.3∘C
e3=x24.70−x25x25×100=±1.21%
e4=x74.7−x75x75×100=±0.4%
So, emax=max(e1, e2, e3, e4)
⇒ emax=±1.21%
Note: While calculating maximum error, we have considered negative deviation. This is because error in above case will be more if negative deviation is taken.
For instance,
e′3=x25.30−x25x25×100
=±1.186% <e3