A ten metre rope tied to a balloon makes an angle of 60- with the ground- The height of the balloon above the ground is

√(3)/2 = h/10 h = 5√(3) h = 8.66m ...

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Question

A ten metre rope tied to a balloon makes an angle of $60^{\circ}$ with the ground. The height of the balloon above the ground is .......................

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Solution

$\frac{\sqrt{3}}{2}$ = $\frac{h}{10}$

h = $5 \sqrt{3}$

h = 8.66m

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A ten metre rope tied to a balloon makes an angle of 60∘ with the ground. The height of the balloon above the ground is .......................

√32 = h10 h = 5√3 h = 8.66m

A ten metre rope tied to a balloon makes an angle of $60^{\circ}$ with the ground. The height of the balloon above the ground is .......................

$\frac{\sqrt{3}}{2}$ = $\frac{h}{10}$

h = $5 \sqrt{3}$

h = 8.66m