A ten metre rope tied to a balloon makes an angle of 60- with the ground- The height of the balloon above the ground is

√(3)/2 = h/10 h = 5√(3) h = 8.66m ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Mathematics

Similar Triangles

A ten metre r...

Question

A ten metre rope tied to a balloon makes an angle of $60^{\circ}$ with the ground. The height of the balloon above the ground is .......................

Open in App

Solution

$\frac{\sqrt{3}}{2}$ = $\frac{h}{10}$

h = $5 \sqrt{3}$

h = 8.66m

Suggest Corrections

Similar questions

Q. A kite is flying at a height of 60 m above the ground. The string attached to the kite is tied at the ground. It makes an angle of 60° with the ground. Assuming that the string is straight, find the length of the string.

(\sqrt{3} = 1.73)

Q. A rope of length

5

metres is tightly tied with one end at the top of a vertical pole and other end to the horizontal ground. If the rope makes an angle

30^{0}

to the horizontal, then the height of the pole is

A circus artist is climbing a 20m long rope which is tightly stretched and tied from the top of a vertical pole to the ground. If the rope makes an agle of $30^{\circ}$ with the ground, then the height of the pole is ___ metres.

A tent 10 m high is tied with a taut rope from the ground to the top of the tent making an angle of elevation of $30^{\circ}$ with the ground. The length of the rope is ___ m

Q. Question 18
The lower window of a house is at a height of 2m above the ground and its upper window is 4m vertically above the lower window. At certain instant the angles of elevation of a balloon from these windows are observed to be

60^{\circ}

and

30^{\circ}

, respectively. Find the height of the balloon above the ground.

Join BYJU'S Learning Program

A ten metre rope tied to a balloon makes an angle of 60∘ with the ground. The height of the balloon above the ground is .......................

√32 = h10 h = 5√3 h = 8.66m

A ten metre rope tied to a balloon makes an angle of $60^{\circ}$ with the ground. The height of the balloon above the ground is .......................

$\frac{\sqrt{3}}{2}$ = $\frac{h}{10}$

h = $5 \sqrt{3}$

h = 8.66m