A tennis ball is hit with a vertical speed of $10 m / s$ upwards and a horizontal speed of $30 m / s$ . How far will the ball travel horizontally before landing?

10 m

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20 m

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40 m

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60 m

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80 m

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Solution

The correct option is D $60 m$
Given,

$v_{0 y} = 10 m / s$

$v_{0 x} = 30 m / s$

$g = 10 m / s^{2}$

In projectile motion, for solving the total distance traveled by the ball horizontally, have to calculate the total time to cover going up and landing down by the given equation,

$y = v_{0 y} t + \frac{1}{2} g t^{2} + y_{0}$

at the point where it lands, $y = 0$

$0 = 10 t + \frac{1}{2} (- 10) t^{2}$

$0 = t (10 - 5 t)$

$t = 0, 2 s e c$

The total horizontal distance covered by the tennis ball is given by

$x = v_{0 x} t$

$x = 30 \times 2$

$x = 60 m$

The correct option is D.

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A tennis ball is hit with a vertical speed of 10m/s upwards and a horizontal speed of 30m/s. How far will the ball travel horizontally before landing?

A tennis ball is hit with a vertical speed of $10 m / s$ upwards and a horizontal speed of $30 m / s$ . How far will the ball travel horizontally before landing?