Question

A Tennis ball is released from a height $h$ and after freely falling on a wooden floor it rebounds and reaches height $\frac{h}{2}.$ The velocity versus height of the ball during its motion may be represented graphically by
(graph are drawn schematically and on not to scale)

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

For uniformly accelerated/decelerated motion,

$v^2=u^2\pm 2gh$

As the equation is quadratic, so $v-h$ graph will be a parabola


Initially velocity is downwards $(-ve)$ and then after collision it reverses its direction with lesser magnitude, i.e., velocity is upwards $(+ve)$ and it rises to half of its initial height $\frac{h}{2}.$

Note that time $t=0$ corresponds to the point on the graph where $h=d$.

Next time, collision takes place at $3$.

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, $\left(C\right)$ is the correct answer.