A tent 10 m high is tied with a taut rope from the ground to the top of the tent making an angle of elevation of $30^{\circ}$ with the ground. The length of the rope is___m

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Solution

Let the length of the string be l .

sin $30^{\circ}$ = $\frac{10}{I}$

$\Rightarrow$ $l$ = $\frac{10}{1 / 2}$ = 20m

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A tent 10 m high is tied with a taut rope from the ground to the top of the tent making an angle of elevation of 30∘ with the ground. The length of the rope is___m

Let the length of the string be l . sin30∘ = 10I ⇒ l = 101/2 = 20m

A tent 10 m high is tied with a taut rope from the ground to the top of the tent making an angle of elevation of $30^{\circ}$ with the ground. The length of the rope is___m

Let the length of the string be l .

sin $30^{\circ}$ = $\frac{10}{I}$

$\Rightarrow$ $l$ = $\frac{10}{1 / 2}$ = 20m