A tent is in the form of a cylinder of diameter 4.2 m and height 4m, surmounted by a cone of equal base and height 2.8 m. Find the volume of tent .

$65.376 m^{3}$

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$68.376 m^{3}$

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$64.376 m^{3}$

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$60.376 m^{3}$

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Solution

The correct option is
B

$68.376 m^{3}$

The total surface area of the tent:

$V = π r^{2} h_{1} + \frac{1}{3} π r^{2} h_{2}$

$π = \frac{22}{7}; r = 2.1 m$

$h_{1} = h e i g h t o f t h e c y l i n d e r = 4 m$

$h_{2} = h e i g h t o f t h e c o n e = 2.8 m$

So,

$V = (\frac{22}{7} \times 2.1 \times 2.1 \times 4 + \frac{1}{3} \times \frac{22}{7} \times 2.1 \times 2.1 \times 2.8) m^{2} = 68.376 m^{3}$

Therefore, the volume of the tent is $68.376 m^{3}$ .

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A tent is in the form of a cylinder of diameter 4.2 m and height 4m, surmounted by a cone of equal base and height 2.8 m. Find the volume of tent .

The correct option is B 68.376m3 The total surface area of the tent: V=πr2 h1+ 13πr2h2 π=227;r=2.1m h1=height of the cylinder=4m h2=height of the cone=2.8m So, V=(227×2.1×2.1×4+13×227×2.1×2.1×2.8)m2=68.376m3 Therefore, the volume of the tent is 68.376m3 .