1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A tent is in the form of a right circular cylinder, surmounted by a cone. The diameter of the cylinder is 24 m. The height of the cylindrical portion is 11 m, while the vertex of the cone is 16 m above the ground. Find the area of the canvas required for the tent is

A
1320m2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3120m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2130m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1230m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A 1320m2Area of canvas required for the tent = Curved surface area of the cylindrical portion + Curved surface area of the cone =(π)rl+2(π)rhFor cylinder:Radius (r) of the cylinder =12 mHeight(h) of the cylinder =11mCurved surface area of cylinder =2πrh=2(π)×12×11=264(π)For cone:Height (h) of the cone = Height of the vertex from ground − Height of the cylinder=16−11=5 mRadius (r) of the cone =12mSlant height of the cone =lml2=r2+h2l=√r2+h2l=√52+122 =13mCurved Surface area of cone =πrl=π(12)(13)=(156π)m2Hence, area of canvas =(264π+156π)m2=(420π)m2=420×227=1320m2.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Questions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program