A tent is of the shape of a right circular cylinder upto a height of $3$ m and then becomes a right circular cone with a maximum height of $13.5$ m above the ground. Calculate the cost of painting the inner side of the tent at the rate of Rs. $2$ per sq m, if the radius of the base is $14$ m.

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Solution

Surface area to be painted = $π r l + 2 π r h^{1}$
= $π r (\sqrt{r^{2} + h^{2}} + h^{1})$
= $\frac{22}{7} \times 14 (\sqrt{14^{2} + {10.5}^{2}} + 3)$
= 44 $\times$ 20.5
= ${902 m}^{2}$
Total cost of painting = Rs. $(902 \times 2)$
= Rs. $1804$

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π = \frac{22}{7}

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A tent is of the shape of a right circular cylinder upto a height of 3 m and then becomes a right circular cone with a maximum height of 13.5 m above the ground. Calculate the cost of painting the inner side of the tent at the rate of Rs. 2 per sq m, if the radius of the base is 14 m.

Surface area to be painted = πrl+2πrh1 = πr(√r2+h2+h1) = 227×14(√142+10.52+3) = 44 × 20.5 = 902m2Total cost of painting = Rs. (902×2) = Rs. 1804

A tent is of the shape of a right circular cylinder upto a height of $3$ m and then becomes a right circular cone with a maximum height of $13.5$ m above the ground. Calculate the cost of painting the inner side of the tent at the rate of Rs. $2$ per sq m, if the radius of the base is $14$ m.

Surface area to be painted = $π r l + 2 π r h^{1}$
= $π r (\sqrt{r^{2} + h^{2}} + h^{1})$
= $\frac{22}{7} \times 14 (\sqrt{14^{2} + {10.5}^{2}} + 3)$
= 44 $\times$ 20.5
= ${902 m}^{2}$
Total cost of painting = Rs. $(902 \times 2)$
= Rs. $1804$