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Question

A term is selected from the expansion of (x+y+z)10 at random. The probability that two variables out of x, y, z have same power is

A
522
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B
311
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C
322
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D
922
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Solution

The correct option is B 311
(x+y+z)10
Total number of terms =12C2=66
Possibilities ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪5,5,04,4,23,3,42,2,61,1,80,0,10
Favourable number of cases = 18
Required probability =1866=311

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