A term is selected from the expansion of (x+y+z)10 at random. The probability that two variables out of x, y, z have same power is
A
522
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B
311
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C
322
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D
922
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Solution
The correct option is B311 (x+y+z)10 Total number of terms =12C2=66 Possibilities ⎧⎪
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⎪⎩5,5,04,4,23,3,42,2,61,1,80,0,10 ∴ Favourable number of cases = 18 ∴ Required probability =1866=311