A test charge $q$ is made to move in the electric field of a point charge $Q$ along two different closed paths (Figure). First path has sections along and perpendicular to lines of electric field. Second path is a rectangular loop of the same area as the first loop. How does the work done compare in the two cases?

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Solution

The electrostatic field is conservative, work done by conservative force in closed path is zero. Here test charge is moving in closed path and field is conservative. So, the work done in both the cases will be zero.

Final Answer: As electric field is conservative, work done will be zero in both the cases.

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