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Question

A tetrahedron has 4 faces and 6 edges. How many vertices does it have?


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Solution

As we know for any polyhedron that doesn't intersect itself,

V-E+F=2

Where ,

V is number of vertices =?

E is number of edges =6

F is number of faces =4

So we have,

V-E+F=2V-6+4=2V-2=2V=2+2V=4

Hence, given tetrahedron have 4 vertices.


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