Question

A tetrahedron is a triangular pyramid with four faces that are identical equilateral triangles. The total lateral surface area of a tetrahedron is 93 square centimeters. Find the surface area of the tetrahedron.

Answer 1

Step 1: Given that:

The total lateral surface area of a tetrahedron is $93c{m}^2$

Step 2: Area of each equilateral triangle $=\frac{93}{3}c{m}^2$

Area of each equilateral triangle $=31c{m}^2$

Step 3: Total surface area of tetrahedron $=(31\times 4)c{m}^2$

Total surface area of tetrahedron $=124c{m}^2$

Final answer: Total surface area of tetrahedron is $124c{m}^2$