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Bohr's Model of Atom

A He+ ion is ...

Question

A ${He}^{+}$ ion is in its first excited state. Its ionization energy is-

A

54.40 eV

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B

13.60 eV

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C

6.04 eV

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D

48.36 eV

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Solution

The correct option is B $13.60 eV$
From, Bohr's atom model, energy of the $n^{t h}$ state is,

$E_{n} = - 13.6 \frac{Z^{2}}{n^{2}}$
Here, $Z = 2; n = 2$
$\Rightarrow E_{2} = \frac{- 13.6 (2)^{2}}{2^{2}} = - 13.6 eV$
$∵ Ionization energy = - Binding energy = 13.6 eV$
 Hence, $(C)$ is the correct answer.

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