Question

$\left(A\right)+\text{tap water}\to \text{white turbidity soluble in aq.}N{H}_3$

$\left(A\right)\stackrel{△}{\to }\text{residue(B)}+N{O}_2+O_2$

Aqueous (A) gives brown ring on adding $FeS{O}_4$ and $conc.H_{2}S{O}_4.$ Identify (A) as:

• A. $NaN{O}_3$
• B. $AgN{O}_3$
• C. $NaN{O}_2$
• D. $AgN{O}_2$

Answer 1

The correct option is B $AgN{O}_3$

$\left(A\right)+\text{tap water}\to \text{white turbidity soluble in aq.}N{H}_3$

Tap water has $C{l}^{-}$ and turbidity is soluble in $aq.N{H}_3.$

Turbidity is of $AgCl$ and thus $\left(A\right)$ has $A{g}^{+}$.

$\left(A\right)$ also gives ring test of $N{O}_3^{-}$.

$\left(A\right)$ has nitrate and thus $\left(A\right)$ is $AgN{O}_3$