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Apparent Weight

A: the Appare...

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A: the Apparent weight of a body in an elevator moving with some downward acceleration is less than the actual weight of a body R: the part of the weight is spent in producing downward acceleration when body is in elevator

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Q. Assertion :The apparent weight of a body in an elevator moving with some downward acceleration is less than the actual weight of a body. Reason: The part of the weight is spent on producing downward acceleration, when body is in elevator.

Q. Assertion :The apparent weight of a body of mass m in an elevator moving with a downward acceleration 'a' is

R = m (g - a)

Reason: The part of weight (mg) spent on producing downward acceleration 'a' is ma. Therefore apparent weight

= m g - m s = m (g - a)

.

50 k g

is standing in a lift moving down with an acceleration

9.8 m / s^{2}

The apparent weight of the body is-

Q. A body of mass

10 k g

is placed in a lift moving upward with an acceleration of

2 m / s^{2}

. The apparent weight of body is

(g = 9.8 m / s^{2})

Q. Statement I: When you are accelerating upwards with some acceleration in a elevator your measured weight will be more than your actual weight.
Statement II: Normal force on you will be more than your weight in any elevator.

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