(a) The head scale of a screw gauge has 200 divisions and its thimble moves by 0.5 mm along the main scale for one complete rotation of the screw. Find its least count.
A
0.00025 cm
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B
0.00025 mm
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C
0.025 mm
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D
0.025 cm
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Solution
The correct option is A 0.00025 cm
Pitch of the screw gauge P=0.5mm
Number of divisions on circular scale N=200
So, least count L.C.=PN=0.5mm200=0.0025mm=0.00025cm