A thermally insulated rigid container contains an ideal gas. It is heated through a resistance coil of 100Ω by passing a current of 1 A for five minutes, then change in internal energy of the gas is
A
0 KJ
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B
30 KJ
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C
10 KJ
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D
20 KJ
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Solution
The correct option is C 30 KJ Heat H supplied to the gas in container: H=i2×R×dt where is is the current in the resistor( 1A), R is the resistance( 100 Ω and dt is the duration of time( 5 mins= 300 secs) ∴H=12×100×300=30000J=30kJ Since the container is rigid, no work is done when the the gas expands. dW=0 in the equation dQ=dU+dW
As the work done is 0 so dQ=dU
Then The change in internal energy is equal to =30kJ