Question

A thermodynamic process is carried out from an intermediate state E by the linear process shown in figure. The total work is done by the gas from D to E to F is:

• A. $100J$
• B. $800J$
• C. $300J$
• D. $250J$

Answer 1

Answer: (B)

$800J$

Solution:- (B) $800J$

Total work done by the gas from D to E to F $=$ Area of $△DEF(\because W_{F\to D}=0)$

Area of $△DEF=\frac{1}{2}\times DF\times EF$

Now, from the given fig.,

$DF=600-200=400N/m^2$

$EF=7-3=4m^3$

Therefore,

Area of $△DEF=\frac{1}{2}\times 400\times 4=800J$

Hence the total work done by the gas from D to E to F is $800J$.