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Question

A thermodynamic process is shown in figure. The pressures and volumes corresponding to some points in the figure are PA=3×104Pa, PB=8×104Pa and VA=2×103m3, VD=5×103m3. In process AB, 600J of heat is added to the system and in process BC, 200J of heat is added to the system. The change in internal energy of the system in process AC would be
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A
560J
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B
800J
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C
600J
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D
640J
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Solution

The correct option is A 560J
No work is done during isochoric process AB.
Work done during isobaric process BC=PB(VCVB)
=PB(VDVA)=240J
From conservation of energy, Q=U+W
U=QW=(600+200)J240J=560J

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