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Question

A thermodynamic process is shown in the following figure. The pressure and volumes corresponding to some points in the figure are :



PA=3×104Pa,VA=2×103m3
PB=8×104Pa,VD=5×103m3

In process AB, 600 J of heat is added and in the process BC, 200 J of heat is added to the system. The change in internal energy of the system in the process AC would be?


A
560 J
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B
800 J
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C
600 J
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D
640 J
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Solution

The correct option is A 560 J
WAC=WAB=WBC=0+8×104(VCVB)
=8×104(VDVA)=8×104(3×103)
=240
dO=dE+WAC
800=dE+240
dE=560

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