Question

A thermodynamic system goes from state (i) $(P,V)$ to $(2P,V)$ and (ii) $(P,V)$ to $(P,2V)$. Work done in the two cases is

• A. Zero, Zero
• B. Zero, $PV$
• C. $PV$, Zero
• D. $PV,PV$

Answer 1

The correct option is B Zero, $PV$


Area under this graph $=0$
$\therefore$ Work done $=0$


Area under graph = Area of rectangle
$=P(2V-V)=PV$
$\therefore$ Work done in case (ii) $=PV$