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Work Done

A thermodynam...

Question

A thermodynamic system goes from state (i) $(P, V)$ to $(2 P, V)$ and (ii) $(P, V)$ to $(P, 2 V)$ as shown in the figure. Work done in the two cases is :

A

Zero, Zero

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B

Zero,

P V

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C

P V

, Zero

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D

P V, P V

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Solution

The correct option is B Zero, $P V$

Area under this graph $= 0$
$∴$ Work done $= 0$

Area under graph = Area of rectangle
$= P (2 V - V) = P V$
$∴$ Work done in case (ii) $= P V$

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