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Question

A thermodynamic system is taken from an original state to an intermediate state by the linear process shown in Its volume is then reduced to the original value from E to F by an isobaric process. Calculate the total work done by the gas from D to E to F

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Solution

Given, the pressure and volume at point F are 300N/ m 2 and 2 m 3 , at point D are 600N/ m 2 and 2 m 3 while at point E are 300N/ m 2 and 5 m 3 .

The total work done by the gas from state D to E to F is the area of the graph subtended by the points. Hence, work done by gas is the area of ΔDEF.

Let W be the work done by the gas, then

W= 1 2 ( FE )( DF )

Substitute the values in the above expression.

W= 1 2 ×( 600300 )×( 52 ) =450J

Hence, the total work done by the gas is 450J.


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