Question

A thermodynamic system undergoes cyclic process $ABCDA$ as shown in fig. The work done by the system in the cycle is:

• A. $P_0{V}_0$
• B. $2P_0{V}_0$
• C. $\frac{P_0{V}_0}{2}$
• D. Zero

Answer 1

The correct option is D Zero

Work done by the system in the cycle = Area under $P-V$ curve & $V-$axis
For clockwise work done is positive
For anticlockwise work done is negative
$W_{ADEA}=+\frac{1}{2}(2P_0-P_0)(2V_0-V_0)$
$W_{EBCE}=-\left(\frac{1}{2}\right)(3P_0-2P_0)(2V_0-V_0)$
$W_{net}=W_{EBCE}+W_{ADEA}=\frac{P_0{V}_0}{2}-\frac{P_0{V}_0}{2}=0$