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Question
A thermodynamical system is changed from state (P1,V1) to (P2,V2) by two different processes. The quantity which will remain same will be:
A thermodynamical system is changed from state (P1,V1) to (P2,V2) by two different processes. The quantity which will remain same will be:
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Solution
The correct option is C q+w
Heat and work done are the properties which depend on the initial and final states as well as the path taken to go from one to the other. These are called path functions.
Sum of heat and work done is called internal energy of the system from the first law of thermodynamics.
Change in internal energy does not depend upon path since it is a state function. So, △U=q+w will remain constant.
Heat and work done are the properties which depend on the initial and final states as well as the path taken to go from one to the other. These are called path functions.
Sum of heat and work done is called internal energy of the system from the first law of thermodynamics.
Change in internal energy does not depend upon path since it is a state function. So, △U=q+w will remain constant.
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